(8/(x^2-3x))=(1/(x^2-9))

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Solution for (8/(x^2-3x))=(1/(x^2-9)) equation:


D( x )

x^2-(3*x) = 0

x^2-9 = 0

x^2-(3*x) = 0

x^2-(3*x) = 0

x^2-3*x = 0

x^2-3*x = 0

DELTA = (-3)^2-(0*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+3)/(1*2) or x = (3-9^(1/2))/(1*2)

x = 3 or x = 0

x^2-9 = 0

x^2-9 = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in (-oo:-3) U (-3:0) U (0:3) U (3:+oo)

8/(x^2-(3*x)) = 1/(x^2-9) // - 1/(x^2-9)

8/(x^2-(3*x))-(1/(x^2-9)) = 0

8/(x^2-3*x)-(x^2-9)^-1 = 0

8/(x^2-3*x)-1/(x^2-9) = 0

x^2-3*x = 0

x^2-3*x = 0

x*(x-3) = 0

x-3 = 0 // + 3

x = 3

x*(x-3) = 0

8/(x*(x-3))-1/(x^2-9) = 0

(8*(x^2-9))/(x*(x-3)*(x^2-9))+(-1*x*(x-3))/(x*(x-3)*(x^2-9)) = 0

8*(x^2-9)-1*x*(x-3) = 0

7*x^2+3*x-72 = 0

7*x^2+3*x-72 = 0

7*x^2+3*x-72 = 0

DELTA = 3^2-(-72*4*7)

DELTA = 2025

DELTA > 0

x = (2025^(1/2)-3)/(2*7) or x = (-2025^(1/2)-3)/(2*7)

x = 3 or x = -24/7

(x+24/7)*(x-3) = 0

((x+24/7)*(x-3))/(x*(x-3)*(x^2-9)) = 0

((x+24/7)*(x-3))/(x*(x-3)*(x^2-9)) = 0 // * x*(x-3)*(x^2-9)

(x+24/7)*(x-3) = 0

( x+24/7 )

x+24/7 = 0 // - 24/7

x = -24/7

( x-3 )

x-3 = 0 // + 3

x = 3

x in { 3}

x = -24/7

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